5+55+555...n terms. Change this term into G.P. then find the sum of this series?

  5+55+555+..........n 

  =5 (1+11+111+........n terms)

  =  5 /9 (9+99+999+....... nterms )

  = 5/9 ( (10 -1 ) + (100-1) + (1000-1) +.....nterms   )

  = 5/9 [(10 +100 + 1000 +......n terms   (GP series ) )  -  (1+1+1+1.......n terms )]

  = 5/9 [  10 ((10)n -1)  /  10-1  ]  - n ]

  = 5/9 [  10 (10n  -1) /9   - n  ]

  =  5 /81 [  10 (10n -1)  -  9n ]

 

  • 9
Follow APC test papers
  • -2
0.5+0.55+0.555+.......+ to n terms
  • 0
What are you looking for?