47. 47. A boy begins to walk eastward along a street infront of his house and the graph of his displacement from house is shown in the following figure. His average speed for the whole time interval is equal to: 47 Share with your friends Share 0 Decoder_2 answered this Dear student,Distance from 0 to 5s =40 mDistance from 5 to 10s = 0 mDistance from 10 to 15s = 60 mDistance from 15 to 20s = 20 mSo, net distance=40+0+60+20 = 120 mTotal time taken = 20 min.Hence, average speed =total distancetime=12020=6m/minRegards 0 View Full Answer