3cos2 π/4+ sec 2π/3 + 5tan2π/4=9/2 Share with your friends Share 0 Varun.Rawat answered this LHS = 3 cos2π4 + sec2π3 + 5 tan2π4=3 cos2π4 + secπ - π3+ 5 tan2π4=3 cos2π4 - sec π3+ 5 tan2π4=3 × 122 - 2 + 5 × 12=32 - 2 + 5=32 + 3=92=RHS 0 View Full Answer
