32.  The velocity of an electron at a point A is 10 7 ms-1 .  Find : (i)  direction and magnitude of the magnetic field due to which the electron will go from A to B on the semi-circular path shown,  (ii)  time taken by the electron in going from A to B.
                                                  [Answer: (i)  1 . 12 × 10 - 3 T , perpendicular to the plane of paper pointing downwards, (ii)   1 . 57 × 10 - 8 s . ]

Dear student,since the centripetal force will be equal to magnetic force so,mv2r=evBB=mver=9.11×10-31×1071.6×10-19×0.05=1.13×10-3TThe direction of the magnetic field will be perpendicular to the plane and directed inwards.t=πrv=3.14×0.05107=1.57×10-8sRegards

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