30% passengers from a train got down at a station A 50% of the remaining passengers got down at station - Maths - Comparing Quantities

Question

30% passengers from a train got down at a station A 50% of
the remaining passengers got down at station B If there were still
350 passangers in the train, how many were there in the train
before station a?

Ankush Jain · Accepted Answer

Let the number of passengers in the train before station A = x

Now, it is given that 30% of the passengers got down at station A.

So, number of passengers deboard at A = 30% of x

Now, the 50% of the remaining passengers got down at station B.

Number of remaining passengers = x - 30% of x

$= x - \frac{30 x}{100} = \frac{70 x}{100}$

So, number of passengers got down at Station B $= 50 % o f \frac{70 x}{100}$

$= \frac{50}{100} \times \frac{70 x}{100} = \frac{35 x}{100}$

Again, number of passengers still left in the train = 350

According to the given condition,

$\frac{30 x}{100} + \frac{35 x}{100} + 350 = x \Rightarrow \frac{65 x}{100} - x = - 350 \Rightarrow \frac{- 35 x}{100} = - 350 \Rightarrow x = 1000$

Hence, the number of passengers in the train before station A = 1000.

30% passengers from a train got down at a station A.50% of the remaining passengers got down at station B.If there were still 350 passangers in the train, how many were there in the train before station a?