24 gm of Na2SO4 was dissolved in water and BaCl2 solution was added to it. What substance will be precipitated and what will be its mass?
Solution:
Na2SO4 + BaCl2 2NaCl + BaSO4
Here BaSO4 formed is the precipitate.
In the question, you have mentioned amound of Na2SO4
24g = 24g/142g/mol = 0.169 mol.
We cannot predict the mass of precipitate unless we know amount of BaCl2.
Na2SO4 + BaCl2 2NaCl + BaSO4
Here BaSO4 formed is the precipitate.
In the question, you have mentioned amound of Na2SO4
24g = 24g/142g/mol = 0.169 mol.
We cannot predict the mass of precipitate unless we know amount of BaCl2.