11th ans pls

11th ans pls 11. A stone is falling freely in free space. Its velocity is x when it has lost y units of potential energy in the gravitational field of earth. The mass of the stone is 2y (2) 2 x — + 9.8 (4) x . Aakash T

  • 4
Given freely falling, so initial velocity U=0;
also potential energy is Y=mgh => m = Y / gh - (1);
by eqn v2 =2gh => h = v2 / 2g; since v=x, h=
x 2
/ 2g  -(2) ;
substitute h in eqn 1
we get  m = 2y / x2
  • 1
What are you looking for?