1)- What is the pH of10-8 (N) HCl?
The pH of 10-8 N HCl can be calculated as follow:
[H+] = 10-8 N
As the solution is so dilute that water will also dissociate to produce H+ ions
H2O → H+ + OH-
The Concentration of H+ released from water is 10-7 as the pH of water is equal to 7.
Hence the total concentration of H+ = 10-7 + 10-8
[H+] = 10-7 + 0.1 × 10-7
= 1.1 × 10-7
pH = -log [H+]
Hence pH = 6.95
Hence the pH of 10-8 N solution of HCl = 6.95.