# 1.The moon is observed from 2 diametrically opposite points A & B on earth. The angle teta subtended at the moon by the 2 directions of observation is 1°54min. Given that the diameter of earth is 1.276*10power 7 metre.Calculate the distance of moon from earth. 2.The Suns angular diameter is 1920sec. The distance of Sun from earth is 1.496*10power11metre. What is the diameter of Sun 3. The escape velocity from surface of earth is given by V=sq root of 2GM/R , where M is mass, R is radius, G is universal gravitational constant. Check the correctness of this equation by using the method of dimension

Dear Student!!

Ans. 1Using the parallax method,

Distance of the moon from the earth,

Ans. 3

Writing the dimension on both the side of the equation.

Dimension on the both side are equal, hence the formula is dimensionally correct.

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some one pls ans this quest....

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We have θ = 1° 54′ = 114′

=(114× 60”)× (4.85 × 10

-6

= 3.32 × 10

-2

since, 1”= 4.85 × 10

-6

Also b = AB =1.276 × 10

7

Hence from Equation (1), we have the earth-moon

distance,

D=

θ

b

=1.276 × 10

7 ÷ 3.32 × 10

-2

=3.84× 10

8

m

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JUST KIDDING

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