1.sum 1 +3/2 +5/4+ 7/8+ ....to infinity 2. SUM 1 + 3/4+7/16+15/64+31/256+.....TO INFINITY SUM 1+2/2+3/2^2+4/2^3+.......TO N TERMS Share with your friends Share 11 Manvendra Singh answered this 1sts=1+32+54+78+----∞So now multiply with 12both side and substract to each other by the following methods=1+32+54+78+----∞s2= 12+34+58+716+---∞So we gets2=1+22+24+28+---∞s2=1+1+12+14+---∞So as we can see that the GP of infinite terms(1+12+14+---∞) Because of the sum of infinite GP is=a1-n⇒n is common ratio=121=12So the sum of this infinite GP is 11-12=2Hences2=1+2s=6Answer2nds=1+34+716+1564+31256+----∞So as we do earlier multiply with 14both the sides and substract to each others4=14+316+764+15256+---∞So now after substraction3s4=1+12+14+18+116+---∞So now as we can see the infinite GP and the sum infinite GP is a1-n⇒Here n is common ratio=121=12Hence the sum of this GP will be 11-12=2So now3s4=2s=83Answer 10 View Full Answer