1. If 3cotA= 4 ,check whether 1- tan2A = cos 2 A – sin 2 A or not

1+ tan2A

2. If tanA= a/b, find the value of cosA + sinA

cosA – sinA

3. If 3 tanA = 4, find the value of 4cosA – sinA

2cosA + sinA

4. If 3cotA = 2, find the value of 4sinA – 3cosA

2sinA + 6cosA

5. If tanA = a/b, prove that asinA – bcosA = a2 – b2

asinA + bcosA a2 + b2

6. If secA = 13/5, show that 2sinA – 3cosA = 3

4sinA – 9cosA

7. If cosA = 12/13, show that sinA(1 - tanA)= 35/156

i dont get hw do we solve such sums... plz help me out......

1).

It is given that 3cot A = 4

Or, cot A =

Consider a right triangle ABC, right-angled at point B.

If AB is 4k, then BC will be 3k, where k is a positive integer.

In ΔABC,

(AC)2 = (AB)2 + (BC)2

= (4k)2 + (3k)2

= 16k2 + 9k2

= 25k2

AC = 5k

cos2 A − sin2 A =

 

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