1 gram of two solutes 'A' and 'B' (molar mass of A > molar mass of B) are dissolved speratly in 100g each of same solvent. Which solute will show greater elevation in boiling point and why?

Dear Student,

The computation is expressed below,


boiling point elevation is,Tb=Kbmiwhere m is molality,molality = moles of solutekg of solventlower molar mass will be having higher boiling point as it dissociates completely in the solution.for example let we take mass = 1 gm, Kb=i=1molar mass of A = 1.1 & molar mass of B = 1ATb=1×11.1100×1=0.00909oCBTb=1×11100×1=0.01oChence B has higher boiling point than A proving lower molar mass is having higher boiling point elevation.
Regards.

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