1 gram of two solutes 'A' and 'B' (molar mass of A molar mass of B) are dissolved - Chemistry - Solutions

Question

1 gram of two solutes 'A' and 'B' (molar mass of A > molar mass
of B) are dissolved speratly in 100g each of same solvent Which
solute will show greater elevation in boiling point and why?

Yasodharan · Accepted Answer

Dear Student,

The computation is expressed below,

boiling point elevation is,∆Tb=Kbmiwhere m is molality,molality = moles of solutekg of solventlower molar mass will be having higher boiling point as it dissociates completely in the solution
for example let we take mass = 1 gm, Kb=i=1molar mass of A = 1
1 & molar mass of B = 1A⇒∆Tb=1×11
1100×1=0 00909oCB⇒∆Tb=1×11100×1=0
01oChence B has higher boiling point than A proving lower molar mass is having higher boiling point elevation
Regards

1 gram of two solutes 'A' and 'B' (molar mass of A > molar mass of B) are dissolved speratly in 100g each of same solvent. Which solute will show greater elevation in boiling point and why?