1) 3 coins are tossed simultaneously. The probability of getting at least two heads is.     Objective (PART A).
(A) 3 10
(B) 3 4
(C) 3 8
(D) 1 2

2) Two cards are drawn successively with replacement for a pack of 52 cards. The probability of drowsing two aces is.
(A) 1 169
(B) 1 221
(C) 1 265
(D) 4 663

3) In a single throw of two dice, the probability of getting more than 7 is
(A) 7 36
(B) 7 12
(C) 5 12
(D) 5 36

Dear Student,

1.Let S be the sample space.S = HHH, HHT, HTH, THH, TTT, TTH, THT, HTTnS = 8Let E be the event of getting at last 2 heads.E = HHH, HHT, HTH, THHnE = 4PE = nEnS = 48 = 122.Total number of cards in a deck = 52Number of aces = 4Pdrawing 2 aces = 452 × 452 = 113 × 113 = 11693.

The required sample space is :
 

∴ Total number of outcomes = 36

nS = 36Let E be the event of getting a total of 7.E = 2,6; 3,5; 3,6; 4,4; 4,5; 4,6; 5,3; 5,4; 5,5; 5,6; 6,2; 6,3; 6,4; 6,5; 6,6nE = 15PE = nEnS = 1536 = 512

Regards

  • 2
good question
  • -2
p(e) = favourable conditions/total number
        = p = 1/2 
q = 1-p = 1-1/2 = 1/2 

hope this helps u
  • 1
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