Find four different solutions of the equation 4x + 5y = 20.
The given linear equation in two variables is 4x + 5y = 20.
We can obtain the solution of the equation by substituting the value of one variable and obtaining the value of the other variable.
If we take x = 0, we obtain
4 × 0 + 5y = 20,
5y = 20
or y = 4
Therefore, (0, 4) is a solution of the given equation.
Now, taking y = 0, we obtain
4x + 5 × 0 = 20
4x = 20
x = 5
Therefore, (5, 0) is a solution of the given equation.
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