Find four different solutions of the equation 4x + 5y = 20.

The given linear equation in two variables is 4x + 5y = 20.

We can obtain the solution of the equation by substituting the value of one variable and obtaining the value of the other variable.

If we take x = 0, we obtain

4 × 0 + 5y = 20,

5y = 20

or y = 4

Therefore, (0, 4) is a solution of the given equation.

Now, taking y = 0, we obtain

4x + 5 × 0 = 20

4x = 20

x = 5

Therefore, (5, 0) is a solution of the given equation.

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if(2,3) and (4,0) lie on the graph of equation ax+by=1. find the value of a and b and plot the graph of the equation obtained