A pentagon may be formed by joining 5 points lying on a plane. However, if we choose 3 or more points which are collinear, then the pentagon will not be formed.

Therefore, here we have 13 non-collinear points and 7 collinear points.

Number of pentagons that can be drawn= ^{13}C_{5}+ ^{13}C_{4}^{7}C_{1}+ ^{13}C_{3}^{7}C_{2}

13. Find the value of x in given figure.

root 12 divided by root 3 ,is not a rational no. as root 12 and root 3 are not integers. TRUE or FALSE ?????

3 root 12 / (upon) 6 root 27 equals

1. 1/2

2. root 3

3. 1/3

4. root 2

Every letter of the English alphabet is coded into numbers like A stands for 1, B for 2 and so on.. Decode the letters used in the phrase RESPECT GIVEN IS RESPECT EARNED. Find the probability of each letter used (only once) to form the phrase from the total sum of all the 27 decoded letters

20 points lie on a plane, out of which 7 points are collinear. Find the number of pentagons that can be drawn?

15373

15474

15383

12298

Time Spent: 1040 seconds

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A pentagon may be formed by joining 5 points lying on a plane. However, if we choose 3 or more points which are collinear, then the pentagon will not be formed.

Therefore, here we have 13 non-collinear points and 7 collinear points.

Number of pentagons that can be drawn

=^{13}C_{5}+^{13}C_{4}^{7}C_{1}+^{13}C_{3}^{7}C_{2}= 1287 + 715 × 7 + 286 × 21 = 1287 + 5005 + 6006 = 12298

The correct answer is D.

how is it

^{13}C_{4}^{7}C_{1}+^{13}C_{3}^{7}C_{2}_{pls can u explain why isit so?}_{}TO CONSTRUCT A SQUARE-ROOT SPIRAL:-TAKE A PIECE OF PLYWOOD HAVING DIMENSIONS 30 cm multiply 30 cm.DRAW A LINE SEGMENT AB OF LENGTH ONE UNIT BY TAKING 2cm = 1 UNIT.CONSTRUCT A PERPENDICULAR BX AT THE LINE SEGMENT AB USING COMPASSES ( OR SET SQUARES ).FROM BX, CUT-OFF BC = 1 UNIT AND JOIN AC.USING RED COLOURED THREAD ( OF LENGHT EQUAL TO AC ) AND ADHESIVE, FIX THIS THREAD ALONG AC.WITH AC AS BASE AND USING COMPASSES ( OR SET SQUARES ), DRAW CY PERPENDICULAR TO AC.FROM CY, CUT-OFF CD = 1 UNIT AND JOIN AD.FIX GREEN COLOURED THREAD ( OF LENGTH EQUAL TO AD) ALONG AD WITH ADHESIVE.WITH AD AS BASE AND USING COMPASSES ( OR SET SQUARES ), DRAW DZ PERPENDICULAR TO AD.FROM DZ, CUT-OFF DE = 1 UNIT AND JOIN AE.FIX BLUE COLOURED THREAD ( OF LENGTH EQUAL TO AE ) WITH ADHESIVENOW REPEAT THE ABOVE PROCESS FOR A SUFFICIENT NUMBER OF TIMES. THIS IS CALLED "A SQUARE ROOT SPIRAL"OBSERVATIONON ACTUAL MEASUREMENT, WE HAVEAC = _________________, AD = ________________,AE = _______________,AF = ______________________,

AG = ___________________,

ROOT 2 = AC = ___________________________ ( APPROX )

ROOT 3 = AD = ________________________

ROOT 4 = AE = __________________

ROOT 5 = AF = __________________

____________________________

____________________________

How to simplify 4 - 2 root 3 by 2

hundredth root (1/4), 200th root (1/8), 300th root(1/32), 400th root (1/8)

1. 300th root (1/32)

2. 400th root (1/64)

3. 200th root (1/8)

4. 100th root (1/4)

what is the simplest rationalization factor of root 5 and why?kindly explain .