if n=m! where ('m' is a positive integer 2 ) then the value of: 1/log2n+1/log3n+ 1/log4n+....+.1/logmn
a)1
b)0
c)-1
d)2
f(x)={e3x-e-5x/x, x not equal to 0
8,x=0
at x=0
if n=m! where ('m' is a positive integer 2 ) then the value of: 1/log2n+1/log3n+ 1/log4n+....+.1/logmn
a)1
b)0
c)-1
d)2