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Bhavyaa Trehan
Subject: Maths
, asked on 22/2/18
Q 10
Q10. In the given figure, n,
l
and m are the length of the sides
LM, MN
and
NL
, respectively of a right angled
∆
LMN
. If r is the radius of the incircle, then prove that 2r = (n +
l +
m).
Answer
2
Hemang Pratap Singh
Subject: Maths
, asked on 21/2/18
Solve this
PQRS is parallelogram where T is the mid point of the side RS and U is the point of intersection of QT and diagonal PR
What is the relation between the length of PU and PR ?
A. 4PU = 3PR B. 3PU = 2PR C. PU = 2PR D. 5PU = 4PR
this:
Answer
2
Rhythm Sehgal
Subject: Maths
, asked on 21/2/18
25) Prove that the ratio of areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. Using the above result do the following.
Answer
1
Pooja Agarwal
Subject: Maths
, asked on 21/2/18
Q.5. In the given figure, if
P
Q
B
C
=
A
P
P
B
=
3
2
, then find the ratio of area of triangle. PAQ to the area of the triangle CAB.
Answer
1
Champ Jee
Subject: Maths
, asked on 19/2/18
Pls experts .... I m asking this que 4th time... Pls help
Q28.
Answer
3
Abhishek
Subject: Maths
, asked on 18/2/18
Simplify the (a^3+b^3) and (a^3-b^3)
Answer
1
Harsh
Subject: Maths
, asked on 18/2/18
Answer the given question with proper steps.
Q.4. In a trapezium ABCD,
A
B
∥
D
C
and DC = 2AB.
E
F
∥
A
B
, where E and F lie on BC and AD respectively such that
B
E
E
C
=
4
3
. Diagonal DB intersects EF at G. Prove that AEF = 11 AB.
Answer
1
Harsh
Subject: Maths
, asked on 18/2/18
Answer the given question with proper steps.
Q.19. In Fig. 3, ABC is a right triangle, right angled at C and D is the mid-point of BC. Prove that
A
B
2
=
4
A
D
2
-
3
A
C
2
.
Answer
1
Simran Raina
Subject: Maths
, asked on 17/2/18
Triangle ABC and triangle DBC are two triangles on the same base. Angle A = angle D = 90. BD meets AC on E.Prove that AE X EC = BE X ED.
Answer
1
Son Ser
Subject: Maths
, asked on 16/2/18
Plzz fast i have exams 2moro. Dont provide any link plzzzzz
Q.
P
D
∥
B
C
P
r
o
v
e
t
h
a
t
:
P
D
B
C
=
A
B
A
P
Answer
4
Champ Jee
Subject: Maths
, asked on 16/2/18
Q28
I get very less frequently math answered questions.
Q28. In the given figure,
PQR
is a triangle where vertices R lies on the circumference of the semicircles with diameters
PQ
and centre
O
.
PRS
and
QS
are the line segments. prove that
PR × PS + QT × QS = PQ.
Answer
1
Rahul
Subject: Maths
, asked on 16/2/18
Solve this:
Answer
2
Rahul
Subject: Maths
, asked on 16/2/18
If?ABC~?DEF find the ar?DEF
Answer
1
Shreya Watwe
Subject: Maths
, asked on 16/2/18
If triangle PQR is isosceles such that PQ=QR and PM is an altitude from P on QR, prove that Angle P =angle Q
Answer
2
Champ Jee
Subject: Maths
, asked on 16/2/18
Solve this :
47
.
I
n
a
∆
A
B
C
,
m
e
d
i
a
n
s
A
D
,
B
E
a
n
d
C
F
i
n
t
e
r
s
e
c
t
s
e
a
c
h
o
t
h
e
r
a
t
G
.
P
r
o
v
e
t
h
a
t
:
3
A
B
+
B
C
+
C
A
>
2
A
D
+
B
E
+
C
F
.
Answer
2
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What are you looking for?
Q10. In the given figure, n, l and m are the length of the sides LM, MN and NL, respectively of a right angled LMN. If r is the radius of the incircle, then prove that 2r = (n + l + m).
PQRS is parallelogram where T is the mid point of the side RS and U is the point of intersection of QT and diagonal PR
What is the relation between the length of PU and PR ?
A. 4PU = 3PR B. 3PU = 2PR C. PU = 2PR D. 5PU = 4PR this:
Q28.
Q.4. In a trapezium ABCD, and DC = 2AB. , where E and F lie on BC and AD respectively such that . Diagonal DB intersects EF at G. Prove that AEF = 11 AB.
Q.19. In Fig. 3, ABC is a right triangle, right angled at C and D is the mid-point of BC. Prove that
Q.
I get very less frequently math answered questions.
Q28. In the given figure, PQR is a triangle where vertices R lies on the circumference of the semicircles with diameters PQ and centre O. PRS and QS are the line segments. prove that PR × PS + QT × QS = PQ.