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Champ Jee
Subject: Maths
, asked on 30/3/18
Q4.
No links pls experts.
This isn't easy as it seems! Please!
Q.4. In
△
A
B
C
,
D
E
∥
B
C
so that AD = (7x - 4) cm, AE = (5x - 2) cm, DE = (3x + 4) cm and EC = 3x cm. Then find the value of x.
Answer
3
Champ Jee
Subject: Maths
, asked on 29/3/18
Q18. In
△
ABC, E and D are points on AB and AC respectively, such that
∠
ADE =
∠
B. If AB = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, then find DE.
Answer
1
Champ Jee
Subject: Maths
, asked on 29/3/18
Que in the pic!
Very confusing!
Q. In the figure, E is the mid-point of side BC of
△
A
B
C
,
C
D
=
1
2
A
C
&
O
E
∥
A
B
∥
C
P
p
r
o
v
e
t
h
a
t
E
F
=
1
/
3
D
F
Answer
3
Raghav Singh
Subject: Maths
, asked on 29/3/18
The pythagoras theorem was given in marhs exam. Now what are the theorems which can come in next exams in section D.
Answer
4
Raghav Singh
Subject: Maths
, asked on 29/3/18
How here diagonal is root 2a
Answer
3
Payal Arora
Subject: Maths
, asked on 28/3/18
Q11
11
.
I
n
a
n
a
c
u
t
e
a
n
g
l
e
d
△
A
B
C
,
A
D
i
s
t
h
e
m
e
d
i
a
n
i
n
i
t
.
P
r
o
v
e
t
h
a
t
:
4
A
D
2
+
B
C
2
=
2
A
B
2
+
2
A
C
2
.
Answer
1
Tushar Minj
Subject: Maths
, asked on 27/3/18
Given∆ABC~∆PQR if AB/PQ =1/3 then find area ∆ABC/∆PQR
Answer
2
Rajeeb Biswas
Subject: Maths
, asked on 27/3/18
Solve this:-
Answer
1
Vipul Gupta
Subject: Maths
, asked on 27/3/18
19. AS, 10). B-15, 15) and C(5,5) are the vertices of ABC. If Dis the midpoint of BMC, find the
Coordinates of D. Also find the coordinates of point P on median AD such that AP /PD 2:3.
Find the area of APBC and compare it with the area of ABC.
Answer
1
Rajeeb Biswas
Subject: Maths
, asked on 27/3/18
Q). AD is the bisector of
∠
B
A
C
, if AB = 10 cm, AC = 6 cm and BC = 12 cm, find BD and DC.
Answer
1
Deeya Katyal
Subject: Maths
, asked on 27/3/18
Q32 pls
Answer
1
Rajeeb Biswas
Subject: Maths
, asked on 27/3/18
Solve this :
45
.
ar
∆
ABC
ar
quad
.
XYCB
=
___________
,
if
XY
∥
BC
.
Answer
1
Manaswini Maheedhar
Subject: Maths
, asked on 27/3/18
good morning sir! i got a doubt on how to name the two similar triangles in a particular question, like they ask you to prove a condition and i get the answer and i find the similar triangles but im not able to name it appropriately.
Answer
4
Yash Behl
Subject: Maths
, asked on 27/3/18
13 , 15:
13. AD is an altitude of an equilateral triangle ABC. On AD as base another equilateral triangle ADE is constructed. Prove that ar (
△
ADE) : ar (
△
ABC)= 3:4.
15. Prove that :
tan
A
1
-
c
o
t
A
+
c
o
t
A
1
-
tan
A
=
1
+
s
e
c
A
.
cos
e
c
A
.
Answer
1
Yash Behl
Subject: Maths
, asked on 27/3/18
14th
Q.14. In the figure,
△
ABC is right angled at C. DE
⊥
AB. If BC = 12 cm, AD = 3 cm, and DC = 2 cm, then prove that
△
ABC
~
△
ADE. Also, find AE and DE.
Answer
2
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What are you looking for?
No links pls experts.
This isn't easy as it seems! Please!
Q.4. In so that AD = (7x - 4) cm, AE = (5x - 2) cm, DE = (3x + 4) cm and EC = 3x cm. Then find the value of x.
Very confusing!
Q. In the figure, E is the mid-point of side BC of
Coordinates of D. Also find the coordinates of point P on median AD such that AP /PD 2:3.
Find the area of APBC and compare it with the area of ABC.
13. AD is an altitude of an equilateral triangle ABC. On AD as base another equilateral triangle ADE is constructed. Prove that ar (ADE) : ar (ABC)= 3:4.
15. Prove that :
Q.14. In the figure, ABC is right angled at C. DE AB. If BC = 12 cm, AD = 3 cm, and DC = 2 cm, then prove that ABCADE. Also, find AE and DE.