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Romil Singh
Subject: Physics
, asked on 15/5/18
Q5 (f)
Q.5. The position of an object moving along a straight line is given by x =
3
-
2
t
2
+
3
t
3
where x is in meters and t in seconds.
(f) Find the average acceleration between t = 2 s and t = 5 s; between t = 1 s and t = 3 s.
Answer
1
Romil Singh
Subject: Physics
, asked on 15/5/18
Solve this:
Q.17. Which of the following figures represents the force of 10 N in a direction of 30
°
east of north?
(A)
(B)
(C)
(D)
Answer
1
Romil Singh
Subject: Physics
, asked on 15/5/18
I
f
A
→
×
B
→
=
A
→
·
B
→
,
t
h
e
n
a
n
g
l
e
b
e
t
w
e
e
n
A
→
a
n
d
B
→
w
i
l
l
b
e
(
A
)
30
°
(
B
)
45
°
(
C
)
60
°
(
D
)
90
°
Answer
3
Maitreyi Singh
Subject: Physics
, asked on 15/5/18
Differentiation of - y= ( cos x)sin x /ln x
Answer
1
Maitreyi Singh
Subject: Physics
, asked on 15/5/18
Y=(cos x) sin x/ ln x
Answer
1
Devansh
Subject: Physics
, asked on 14/5/18
Q). Sir in the above question you have asked only the average velocity, then why did you find displacement by using formula
(
s
=
u
t
+
1
2
a
t
2
)
and then find average velocity. Why you did not find average velocity directly?
Answer
3
Romil Singh
Subject: Physics
, asked on 14/5/18
Solve this: Section R At t = O a car is moving east at 10 m / s. Find its average acceleration between t = O and each of the following times at which it has the given velocities :
(a) t = 2 s, 15 m/ s east
(b) t = 10 s, 10 m/ s west
Answer
2
Aditya Nagesh
Subject: Physics
, asked on 14/5/18
A body undergoes circular motion. The radius of that very circle is R . In twenty minutes it finishes one full rotation. Please find the displacement for twenty as well as forty-five minutes.
Answer
1
Romil Singh
Subject: Physics
, asked on 13/5/18
Let
A
→
=
5
→
i
-
4
→
j
and
B
→
=
-
7
·
5
→
i
6
→
j
.
Do we have
B
→
=
k
A
→
? Can we say
B
→
A
→
=
k
?
Answer
1
Romil Singh
Subject: Physics
, asked on 13/5/18
Find the resultant of the three vectors
O
A
→
,
O
B
→
and
O
C
→
shown in figure (2-W4). Radius of the circle is R.
Answer
2
Romil Singh
Subject: Physics
, asked on 11/5/18
Please no link 30.
Figure shows a regular hexagon abcdef with o as centre. The correct expression about the hexagon is
A
a
b
→
+
a
c
→
+
a
d
→
+
a
e
→
+
a
→
f
=
6
a
o
→
(
B
)
a
b
→
+
a
c
→
+
a
d
→
+
a
e
→
+
a
f
→
=
3
a
o
→
C
a
b
→
+
a
c
→
+
a
d
→
+
a
e
→
+
a
f
→
=
0
→
(
D
)
a
b
→
+
a
c
→
+
a
d
→
+
a
e
→
+
a
f
→
=
2
a
o
→
Answer
1
Romil Singh
Subject: Physics
, asked on 10/5/18
Solve this:
Answer
2
Romil Singh
Subject: Physics
, asked on 10/5/18
How to find theta
Cos ( theta +20 ) = - cos theta
Answer
2
Romil Singh
Subject: Physics
, asked on 10/5/18
Q). How to find theta.
cos
θ
+
2
θ
=
-
cos
θ
Answer
1
Romil Singh
Subject: Physics
, asked on 10/5/18
Q.88. Two vectors lies with their tails at the same point. When the angle between them is increased by 20
°
their scalar product has the same magnitude but changes from positive to negative. The original angle between them was:
(A) 90
°
(B) 60
°
(C) 70
°
(D) 80
°
Answer
1
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What are you looking for?
Q.5. The position of an object moving along a straight line is given by x = where x is in meters and t in seconds.
(f) Find the average acceleration between t = 2 s and t = 5 s; between t = 1 s and t = 3 s.
Q.17. Which of the following figures represents the force of 10 N in a direction of 30 east of north?
(A)
(B)
(C)
(D)
(a) t = 2 s, 15 m/ s east
(b) t = 10 s, 10 m/ s west
Do we have ? Can we say = k?
Figure shows a regular hexagon abcdef with o as centre. The correct expression about the hexagon is
Cos ( theta +20 ) = - cos theta
(A) 90
(B) 60
(C) 70
(D) 80