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## A parallel plate capacitor each with plate area A and separation ‘d’ is charged to a potential difference V. The battery used to charge (i) remains connected (ii) disconnected. A dielectric slab of thickness d and dielectric constant K is now placed between the plates. What change, if any, will take place in (i) charge on the plates, (ii) electric field intensity between the plates, (iii) capacitance of the capacitor? Justify your answer in each case.

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