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Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
A dishonest tradesman marks his goods at an advance of 10% on the C.P. but uses a fraudential balance, which has a horizontal beam when the weigth in one scale is one-fifth more than the weight in the other. How much did he gain?
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
Ram bought a British soap bearing a duty of 25%, and sold it at a loss of 5%. If he would have sold it for Rs. 15 more, he would have cleared 1% on his bargain. What was the C.P of the soap?
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
A seller marked the price of a saree as Rs. 200 and sells the saree at 10% discount. If the ratio of purchase price and sell price be 5: 6 what percentage of gain is there?
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
A tea merchant mixes 4 kg of Darjeeing tea of Rs. 100 per kg with 12 kg of Assam tea of Rs. 50 per kg. and makes a special blend of tea. He sells the new blend of tea at Rs. 70 per kg. Calculate his gain of loss.
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
A furniture maker bought a table and a chair for Rs. 1000. He sold the table at a profit of 10% and the chair at a profit of 20%. If he sold the table at a profit of 20% and the chair at a profit of 15% the sale proceeds would have been Rs. 40 more. Find the cost price of the table and the chair.
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
A trader is allowing 5% trade discount on his list price, then a further discount of 5% to a registered dealer under Sales Tax Act, then a special discount of 21% for purchases above Rs. 1000 and further a Cash discount of 1% for making payment within 10 days. The registered dealer made a payment on 4th December of Rs. 13938-21 net for an invoice sent to him on 26th November. What was the price of the goods purchased by him?
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
In what ratio should rice at Rs. 17.50 per kg. be mixed with rice Rs. 18.50 per kg. so
that the price of each kg. of the mixed rice may be Rs. 18.10
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
Sugar at Rs. 136 a quintal is mixed with sugar at Rs. 141 a quintal in the ratio 2:3. Find the cost of one quintal of the mixture.
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
If a³ + b³ + c3 = 3abc, then either a + b + c = 0 or, a = b = c.
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 18 hours ago
If s = a + b + c, then prove that,
(as + bc)(bs+ca)(cs + ab) = (b + c)²(c + a)²(a + b)².
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 19 hours ago
Prove the following identities:
1. (b + c)(b-c)+(c + a)(c-a) + (a + b)(a - b)=0
2. (b-c)(b²+ bc + c²)+(c-a)(c²+ca + a²) = (b-
a)(b² + ab + a²)
3. (a−b)³ + (a²-b²)(a + b) = 2(a - b)(a² + b²)
4. (x+y)(x+z)-x² = (y + 2)(y + x)-²
= (z+x)(z+y)-z²
5. (1+a)²(1+b²)-(1 + a²)(1+b)² =2(a-b)(1-ab)
6. (1+a²)(1+b²) - (a + b)² = 1 - 2ab + a²b²
7. (a-b+c)(a +b-c)-a²=-(b-c)²
8. (a²-b²)(x² - y2)+4abxy = (ax+by)²-(bx-ay)²
9. (ax + by)2 + (ay-bx)² + c² (x² + y²)
= (a² + b² + c²)(x² + y²)
10. (x + b + 1)(a + 1) −(x + a + 1)(b + 1)=x (a−b)
11. (a + b)²-(c+d)² + (a + c)²(b + d)² = 2(a−d)(a
+b+c+d)
12. (a+b+c)³=a³ + b³ + c³+3(a + b)(b + c)(c + a)
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 19 hours ago
If 2s = a + b + c, then prove that, 2b²c² +2c²a²
+2a²b²-a²-b4 c4 = 16s(sa)(s - b)(s-c).
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 19 hours ago
If x=b+c-a, y = c+a-b, z = a + b -c, then prove that,x³+³+z³ − 3xyz = 4(a³ + b³ + c³-3abc).
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 19 hours ago
If a = y + z, b = z + x, c = x + y, then prove that, a³ + b³ + c³-3abc = 2(x³ +³ +2³-3xyz).
Answer
0
Uddipan Mondal
Subject: Maths
, asked 5 days, 19 hours ago
If a² + b² + c² = ab + bc + ca, prove that, a³ + b³ + c³ = 3abc.
Answer
0
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What are you looking for?

that the price of each kg. of the mixed rice may be Rs. 18.10

(as + bc)(bs+ca)(cs + ab) = (b + c)²(c + a)²(a + b)².

1. (b + c)(b-c)+(c + a)(c-a) + (a + b)(a - b)=0

2. (b-c)(b²+ bc + c²)+(c-a)(c²+ca + a²) = (b-

a)(b² + ab + a²)

3. (a−b)³ + (a²-b²)(a + b) = 2(a - b)(a² + b²)

4. (x+y)(x+z)-x² = (y + 2)(y + x)-²

= (z+x)(z+y)-z²

5. (1+a)²(1+b²)-(1 + a²)(1+b)² =2(a-b)(1-ab)

6. (1+a²)(1+b²) - (a + b)² = 1 - 2ab + a²b²

7. (a-b+c)(a +b-c)-a²=-(b-c)²

8. (a²-b²)(x² - y2)+4abxy = (ax+by)²-(bx-ay)²

9. (ax + by)2 + (ay-bx)² + c² (x² + y²)

= (a² + b² + c²)(x² + y²)

10. (x + b + 1)(a + 1) −(x + a + 1)(b + 1)=x (a−b)

11. (a + b)²-(c+d)² + (a + c)²(b + d)² = 2(a−d)(a

+b+c+d)

12. (a+b+c)³=a³ + b³ + c³+3(a + b)(b + c)(c + a)

+2a²b²-a²-b4 c4 = 16s(sa)(s - b)(s-c).